Electric Fundamentals

Belangrijke formules

Last updated 5 years ago

$B=\frac{\varphi }{A}$

${\mu }_{0}=4.\pi .{10}^{-7}$

$\mathcal{R}=\frac{l}{\mu \times A }$

${u}_{ind}={B}_{\perp }\times l\times v$

$F=B.I.l$

$W=\frac{1}{2}.L.{i}^{2}$

$L={N}^{2}. \frac{ {\mu }_{r}.{\mu }_{0}.A}{l }$

${U}_{L}=L.\frac{dI}{dt}$

${L}_{t}= {L}_{1}+{L}_{2}+\dots +{L}_{n}$

${L}_{t}=\frac{1}{\frac{1}{ {L}_{1}}+\frac{1}{ {L}_{2}}+\dots +\frac{1}{ {L}_{n}}}$

$\tau =\frac{L}{R}$

$i={I}_{max}\times \left(1-{e}^{-\frac{L}{R}\times t}\right)$

${u}_{L1}={U}_{bron} \times {e}^{-\frac{R}{L}t}$

${u}_{R1}={U}_{bron} \times (1- {e}^{-\frac{R}{L}t})$

${ {u}_{L1}= -{U}_{R1 max}\mathrm{ }\times e}^{-\frac{R}{L}t}$

${ {u}_{R1}= {U}_{R1 max}\mathrm{ }\times e}^{-\frac{R}{L}t}$

Stroom door de serieschakeling $RL$ tijdens het ontladen

${i=\frac{ {U}_{R1Max}}{ {R}_{1}}\times e}^{-\frac{R}{L}t}$

${X}_{L}= 2 \pi f L\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }$

${X}_{Lt}={X}_{L1}+{X}_{L2}+\dots . {X}_{Ln}$

${X}_{ {L}_{t}}=\frac{1}{\frac{1}{ {X}_{L1}}+\frac{1}{ {X}_{L2}}+\dots +\frac{1}{ {X}_{Ln}}}$

${P}_{werkelijk}={I}_{eff}^{2} \times {R}_{W}$

${P}_{r}={I}_{eff}\times {U}_{eff}$

${P}_{r}=\frac{ {U}_{eff}^{2}}{ {X}_{L}}$

${P}_{r}={I}_{eff}^{2}\mathrm{ }\times {X}_{L}$

$Q=\frac{ {X}_{L}}{ {R}_{W}}$